In a parallelogram abcd point k belongs to diagonal bd so that bk: dk=1: 4. if the extension of ak meets bc at point e, what is the ratio of be: ec?

BE:EC= 1/3

Step-by-step explanation:

Given ABCD is a parallelogram, Point K is such that it belongs to diagonal BD so that BK:DK=1:4.

If we make an extension of AK which meets BS at point E, then using ΔDKA and ΔEKB, we have

∠DKA=∠EKB (Vertically opposite angles)

∠KDA=∠KBE (Alternate interior angles)

∠DAK=∠BEK (Alternate interior angles)

Thus by AAA similarity,ΔDKA≅ΔEKB

⇒= ,

Since, AD= BC,therefore

= =

Now, BC= BE+EC, ⇒=

⇒1+

⇒

Reciprocating on both the sides, we get

f(x)=2/3x+4/3 is the answer because is whose power in the senate is equal to the power of the speaker of the house?

step-by-step explanation: