The box plots below show the ages of college students in different math courses

4. The mean and median age are most likely to be same for the students in Math 1.

Step-by-step explanation:

We have been given two box plots that show the ages of college students in different math courses. We are asked to choose the true statement about these box plots.

1. The median age of the students in math 1 is greater than the median age of the students in math 2.  

We can see from our given box plots that median age for both Math 1 and Math 2 is 19 that is represented by vertical middle line of box, therefore, 1st statement is not true.

2. The median age of the students in math 1 is less than the median age of the students in math 2.

Since median ages for students in Math 1 and Math 2 are same (19), therefore, 2nd statement is not true.

3. The mean and median age are most likely same for both sets of data.

We can see that box plot for ages of Math 1 students is symmetric, therefore, both mean and median will be same for Math 1 students.

The box plot representing ages of Math 2 students is skewed right as it has an outlier as 23, therefore, its mean age will be greater than median age.

Therefore, 3rd statement is not true either.

4. The mean and median age are most likely to be same for the students in Math 1.

We can see that box plot representing ages for Math 1 students is symmetric and its whiskers are equidistant from median. So both mean and median age are same that is 19, therefore, 4th statement is true.

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2

my dear correct answer is option number 3