How far apart are the foci of an ellipse with a major axis of 10 feet and a minor axis of 6 feet?

The focii are 8 feet apart

Step-by-step explanation:

You can use the formula

F = √(a^2 - b^2)   where F is the distance of the focii from the center , a = length of the semi major axis and b = length of the semi minor axis)

So here it is  √(5^2 - 3^2)

= √16 = 4

So the distance is 2*4 = 8

Quadratic relations and comic sections unit test part 1

12. b. 8 feet

1. b ellipse

domain -4<=x<=4

range -3<=y<=3

2. c. x^2/3

3. c. 1/10 x^2

4. b. 5 inches

5. d. x=1/12 (y-4)^2 +2

6. b. (x-4)^2 + (y-5)^2 =49

7. b. (x+8)^2 + (y+4)^2 =25

8. d. (x+3)^2 + (y+2)^2 =9

9. a. center at (7,-6); radius 4

10. b. x^2/25 + y^2/169 =1

11. a. (0, +/- 6)

12. b. 8 ft

13. c. (put equation in graphing calculator to see graph)

14. d. (0, +/-5)

f(x) is the value of the function. b is the value of the function when x equals zero or the y-coordinate of the point where the line crosses the y-axis in the coordinate plane.

step-by-step explanation:

hope this !

b is 38 degrees.

a is 52 degrees.

this is because if b is 38 and a is 14 degrees more than b than 38+14=52 and 52+38=90 degrees. hope this .