What is the remainder r when the polynomial p(x) is divided by (x - 2)? is (x - 2) a factor of p(x)? p(x) = -4x4 + 6x3 + 8x2 - 6x - 4 a) r = 0, no b) r = 0, yes c) r = -72, no d) r = -72, yes

B

(x-2) is a factor since remainder is 0.

Step-by-step explanation:

We divide (x-2) into the polynomial through long division or synthetic. We choose long division and look for what will multiply with (x-2) to make the polynomial .

We subtract this from the original .

This leaves . We repeat the step above.

.

We subtract this from . We repeat the step above.

.

We subtract this from . We repeat the step above.

.

We subtract this from . There is no remainder. This means (x-2) is a factor.

80° is the measure of gh

step-by-step explanation:

circle f is congruent to circle j

we have two circle with center f and j.

both circles are congruent. the radius of the circle would be equal.

see the attachment for the circle.

we are given ∠efd ≅ ∠gjh

therefore, arc (ed) = arc (gh)     (∴ circle f is congruent to circle j)

but ∠dfe=80°=arc (ed)

therefore, arc (gh) = 80°

thus, 80° is the measure of gh