If one card is drawn from a standard 52- card deck and not replaced, what is the probabity of getting an ace on the next draw?

The probability is about 7.7%

Step-by-step explanation:

A probability is the ratio of the number of relevant outcomes and the number of all possible outcomes. To answer this question we do some counting first:

Consider two draws. We are interested in the second draw being an Ace, the first draw can either be an Ace or not, so, there are two cases of a relevant outcomes (all without replacement):

(number of relevant oucomes n ) = (number of cases of Ace-Ace draws) + (number of cases of NonAce-Ace draws):

(number of possible outcomes) = (number of choices at first draw) * (number of choices at second draw) = 52 * 51 = 2652

The probability is then

P = 204/2652 = 0.0769, or about 7.7%

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option