Write the equation of a line that is perpendicular to the given line and that passes through the given point. y-3=-1/5(x+2); (-2, 7) a. y=5x+7 b. y=5x+17 c. y=(1/5)x-2 d. y=-2x+3 plz answer you : ) < 3

The equation would be B) y = 5x + 17

Step-by-step explanation:

To start, you need to locate the slope of the first equation. Since the slope is the coefficient of x, we know it to be -1/5. Now, the perpendicular slope is the opposite and reciprocal of that, which makes the new slope 5.

Now that we have this, we can use the point and the slope in point-slope form to get the equation.

y - y1 = m(x - x1)

y - 7 = 5(x + 2)

y - 7 = 5x + 10

y = 5x + 17

the rocket cannot penetrate the ground, in a contextual sense, therefore the roots of this equation should be the domain of this function. i'll let you find the roots of this quadratic equation (hint: use the quadratic formula:  

1- c

2-a

step-by-step explanation:

mark brainliest!