F(x) = 4x4 − 8x3 − 3x2 + 7x − 2 = (x + 1)(4x3 − 12x2 + 9x − 2) based on the sythetic division shown, 1 2 is of the polynomial.

Second half of the question:  Based on the synthetic division shown, 1/2 is DEFINITELY A ROOT of the polynomial.

Step-by-step explanation:

-1, 2, 0.5, 0.5

Step-by-step explanation:

Using synthetic division for x=-1 we find that

-1             4    -8      -3    7   -2

                    -4       12   -9    2

-----------------------------------------------

              4     -12    9     -2    0

----------------------------------------------

Thus quotient is

Again try synthetic division by x-2

2            4    -12    9    -2

                      8   -8     2

-----------------------------------

             4   -4      1       0

--------------------------------------

Thus quotient is

Hence zeroes of the polynomial f(x) are

-1, 2, 0.5, 0.5

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this

x -

median = 1.25

range = 12-14.5

interquartile = q12-q14.5

y -

median = 1

range = 15-17

interquartile = q15-q17