Travis can afford a $260-per-month car payment, and he is interested in either a compact car, which costs $10800, or a coupe, which costs 11,300. if he is being offered a 4-year car loan with and apr of 6%, compounded monthly, which car can travis afford?

travis can afford the compact car but not the coupe

Step-by-step explanation:

Travis can afford the compact car.

Step-by-step explanation:

The EMI formula is :

In first case:

p = 10800

r = 6/12/100=0.005

n = 4*12 = 48

Putting values in the formula we get:

= $254

We can see that Travis can afford the compact car because the EMI is less than $260.

In second case:

p = 11300

r = 6/12/100=0.005

n = 4*12 = 48

Putting values in the formula we get:

= $265.75

We can see that the coupe will have an EMI of $265.75 which is higher than the amount that Travis can afford.

Hence, Travis can afford a compact car.

in mathematics, a constraint is a condition of an optimization problem that the solution must satisfy. there are several types of constraints—primarily equality constraints, inequality constraints, and integer constraints. the set of candidate solutions that satisfy all constraints is called the feasible set.

hoped i'm right lol

df =

both have same length