Explain scott works as a delivery person for a shipping company. the graph shows a linear model for his delivery times on different days. (a)what is the equation of the line, first written in point-slope form and then written in slope-intercept form? show how you determined the equation. (b)based on the linear model, predict how long it initially took scott to deliver his packages. approximately how much did his delivery time decrease per day?

y-12= -3(x-6) (point slope form)

y = -3x + 30  ( slope intercept form)

Initial delivery time = 30 minutes

delivery time decreases 3 minutes per day

Step-by-step explanation:

To find equation of line we pick two points from the graph

(3,21)  and (6,12)

Point slope form of a line is y-y1= m(x-x1)

m is the slope and (x1,y1) is the point on graph

Lets find out slope m

(x1,y1) is (6,12)

Point slope form of a line is y-y1= m(x-x1)

y-12= -3(x-6) (point slope form)

Now we solve for y to get slope intercept form

y-12 = -3x +18

Add 12 on both sides

y = -3x + 30  ( slope intercept form)

(b) To find initial time we plug in 0 for x

y = -3x + 30

y= -3(0) + 30

y=30

Initial delivery time = 30 minutes

Slope is the delivery time decreases per day

We got slope m = -3

So delivery time decreases 3 minutes per day

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

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