Andy has 9 math books and 6 reading books. if he wants to distribute them evenly among some bookshelves so that each has the same combination of books, with none left over, what is the greatest number of bookshelves andy can use?

3 is the greatest number of book shelves Andy can use.

Step-by-step explanation:

You can solve this by finding the greatest common factor of 9 and 6, which turned out to be 3.

6/3 = 2 (reading books per shelf)

9/3 =3 (math books per shelf)

Every shelf there are 2 reading books and 3 math books.

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!

answer: 5

step-by-step explanation: