Ametalworker has a metal alloy that is 20% copper and another alloy that is 60% copper. how many kilograms of each alloy should the metalworker combine to create 80 kg of a 52% copper alloy?

16 kg of I type and 64 kg of II type should be mixed.

Step-by-step explanation:

Given that a metal alloy in original has 20% copper and 80% other metals.

Another mixture contains 60% copper and 40% other metals.

We have to get a new alloy of 80 kg which has 52% copper.

Let us assume that we mix x kg of I alloy and y kg of second alloy.

Then we have x+y = total weight = 80 kg.

x+y = 80   ... (i)

Next condition is that new alloy has 52% copper in it

When we mix x kg of I, and y kg of II, copper content would be

0.2x+0.6y.  This equals 52% of 80 = 41.6

Or Dividing by 0.2 we get

x+3y =208  ... (ii)

(ii)-(i) gives 2y = 128 or y =64 kg

x = 16 kg

16 kg of I type and 64 kg of II type should be mixed.

Verify:

Copper in new alloy = 16(0.2) + 64(0.6) = 3.2+38.4 = 41.6

= 52% of 80

use an equation of ratios to determine the amount of gas needed to fill the tank.

    0.2             0.8

  =    

288.75             x

                                                              231 gal

so, 0.2x = (0.8)(288.75 gal), and x = = 1155 gal.

                                                                0.2

it would take 1155 gal. to fill the tank.

the cost would be

1155 gal         $3

* = $3465   (answer)

      1           1 gal

hope this you

-2x + 7 = 7

subtract 7 from both sides.

-2x = 0

divide both sides by -2.

x = 0