Edison has a sales job and receives $45,448 as his annual pay, plus commission. his company pays him a commission of 15% on his total sales. if he makes sales of $25,000 in the first 3 months, how much will he be paid for those 3 months?

Edison will be paid $15,112 for 3 months

Step-by-step explanation:

Edison receives an annual fixed pay = $45,448.

Monthly pay  = 45,448/12 = $3787.33

3-month salary = $3787.33 *3 = $11.362

Commission = 15%

Total sale = $25,000 for the first 3 months.

Commission amount = 25,000*0.15 = $3750

Therefore, total pay that Edison received during first 3 months= salary + commission

= $11,362 + $3750

= $15,112

Thank you.

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2