Explain how to do the problem not just give the answer will mark brainiest

1 Convert
5
2
3
5
​3
​
​2
​​ to improper fraction. Use this rule:
a
b
c
=
a
c
+
b
c
a
​c
​
​b
​​ =
​c
​
​ac+b
​​
5
×
3
+
2
3
−
3
3
4
=
1
+
2
3
+
3
4
​3
​
​5×3+2
​​ −3
​4
​
​3
​​ =1+
​3
​
​2
​​ +
​4
​
​3
​​

2 Simplify
5
×
3
5×3 to
1
5
15
1
5
+
2
3
−
3
3
4
=
1
+
2
3
+
3
4
​3
​
​15+2
​​ −3
​4
​
​3
​​ =1+
​3
​
​2
​​ +
​4
​
​3
​​

3 Simplify
1
5
+
2
15+2 to
1
7
17
1
7
3
−
3
3
4
=
1
+
2
3
+
3
4
​3
​
​17
​​ −3
​4
​
​3
​​ =1+
​3
​
​2
​​ +
​4
​
​3
​​

4 Convert
3
3
4
3
​4
​
​3
​​ to improper fraction. Use this rule:
a
b
c
=
a
c
+
b
c
a
​c
​
​b
​​ =
​c
​
​ac+b
​​
1
7
3
−
3
×
4
+
3
4
=
1
+
2
3
+
3
4
​3
​
​17
​​ −
​4
​
​3×4+3
​​ =1+
​3
​
​2
​​ +
​4
​
​3
​​

5 Simplify
3
×
4
3×4 to
1
2
12
1
7
3
−
1
2
+
3
4
=
1
+
2
3
+
3
4
​3
​
​17
​​ −
​4
​
​12+3
​​ =1+
​3
​
​2
​​ +
​4
​
​3
​​

6 Simplify
1
2
+
3
12+3 to
1
5
15
1
7
3
−
1
5
4
=
1
+
2
3
+
3
4
​3
​
​17
​​ −
​4
​
​15
​​ =1+
​3
​
​2
​​ +
​4
​
​3
​​

7 Find the Least Common Denominator (LCD) of
1
7
3
,
1
5
4
​3
​
​17
​​ ,
​4
​
​15
​​
Method 1: By Listing Multiples
List out all multiples of each denominator, and find the first common one.
Multiples of 3 : 3, 6, 9, 12, ...
Multiples of 4 : 4, 8, 12, ...
Therefore, the LCD is
1
2
12.
Method 2: By Prime Factors
List all prime factors of each denominator, and find the union of these primes.
Prime Factors of 3 : 3
Prime Factors of 4 : 2, 2
Therefore, the LCD is
2
×
2
×
3
=
1
2
2×2×3=12.

Ithink it is 7. 16