What is the equation of the line that pases through (-2,2) and (1,-4)?

The equation of the line that passes through is Y=-2x-2

Step by step:



So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

Now, what about b, the y-intercept?

To find b, think about what your (x,y) points mean:

(-2,2). When x of the line is -2, y of the line must be2.

(1,-4). When x of the line is 1, y of the line must be-4.

Now plug in x and y

You can use either (x,y) point you want..the answer will be the same:

(-2,2). y=mx+b or 2=-2 × -2+b, or solving for b: b=2-(-2)(-2). b=-2.

(1,-4). y=mx+b or -4=-2 × 1+b, or solving for b: b=-4-(-2)(1). b=-2.

See! In both cases we got the same value for b. And this completes our problem.

The equation of the line that passes through the points (-2,2) and (1,-4) is:

128/3reason being 5 and 1/3 = 16/316/3 • 2/3 = 32/31 and 1/3 = 4/3 32/3 • 4/3 this will equal 128/3

The answer that i got was 8/3