How do i calculate slope using this equation y = mx + b the coordinates i'm using are 63, 62 and 47,48. note i'm using a scatter plot and i have to find the slope of it. give answer!

To find slope you have to do rise over run. Use a graphing calculator such as desmos, and enter those cords. Find your y-intercept then see how much up and to the side you can go until hitting a point

Step-by-step explanation:

ok

step-by-step explanation:

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.