What is the value of y in the solution to the following system kid equations 5x-3y=-11 2x-6y=-14

y = 2

Step-by-step explanation:

given the 2 equations

5x - 3y = - 11 → (1)

2x - 6y = - 14 → (2)

multiply (1) by - 2, to eliminate the term in y

- 10x + 6y = 22 → (3)

add (2) and (3) term by term

(2x - 10x) + (- 6y + 6y) = (- 14 + 22)

- 8x = 8 ( divide both sides by - 8 )

x = - 1

substitute x = - 1 into either (1) or (2) and solve for y

(1) : - 5 - 3y = - 11 ( add 5 to both sides )

- 3y = - 6 ( divide both sides by - 3 )

y = 2

solution is (- 1, 2 )

check the picture below.

well, the angle at the vertex d is clearly not a right-angle, let's check for the one at the vertex f which does look like,   however if it's indeed, that means ef is perpendicular to df, in which case their slopes will be negative reciprocal of each other.

so the negative reciprocal of the slope of ef is 1, however the slope of df is not 1, is 1/2, so nope, they're not perpendicular lines.