Acooler contains eleven bottles of sports drink: five lemon-line flavored and six orange flavored. you randomly grab a bottle and give it to your friend. then, you randomly grab a bottle for yourself. your friend gets a lemon-line and you get an orange. a. 1/16=.063 b. 1/36=.028 c. 36/169=.213 d. 3/11=.273 and explain!

The probability that you would choose lemon-lime and then orange is 3/11 =.273.  

Step-by-step explanation:

These are 'dependent events', which mean that your the event is affected by previous events.  So, because you have eleven total bottles (five lemon-lime and six orange) and you do not replace the first bottle, that would only leave you with ten bottles remaining.  The probability that you will pick the lemon-lime on the first choice is 5/11 because all of the bottles are there.  However, your second choice will only include ten total bottles since you already took one.  The probability that you would choose orange would be 6/10.  When you multiply these two fractions and reduce to simplest form, you get 3/11.  

the answer is a

step-by-step explanation:

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841