Which is the simplified form of the expression 3(7/5x+4)-2(3/2-5/4x)

Simplify 7/5x to 7x/5

3(7x/5 + 4) -2(3/2 - 5/4x)

Simplify 5/4x to 5x/4

3(7x/5 + 4) -2(3/2 - 5x/4)

Expand

21x/5 + 12 - 3 + 5x/2

Collect like terms

(21x/5 + 5x/2) + (12 - 3)

Simplify

67x/10 + 9

The answer was b on my test

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

the answer is y < -3 or   y > 3

-3y > 7 + 2

-3 y > 9

y < -3