One hundred grams of plutonium is stored in a container. the amount p (in grams) of plutonium present after t years can be modeled by the equation: p=100(0.00007)t. how much plutonium is present after 20,000 years?

That equation is not typed correctly.  Radioactivity decreases by what is known as exponential decay.

Pu 239 has a half-life of  24,100 years.  

We need to calculate lambda which is natural log (2) / half-life

lambda = .693147 / 24,100 = 2.876 x 10^-5

Amount remaining = beginning amount • e ^ ( -λ • time )

Amount remaining = 100 * 2.718281828^(-2.876 x 10^-5 * 20,000)

Amount remaining = 100 * 2.718281828^-.5752

Amount remaining = 100 * 0.5625923391

Amount remaining after 20,000 years = 56.25923391 grams

Source: https://www.1728.org/halflif2.htm

Step-by-step explanation:

true

step-by-step explanation:

45.36 feet per second

step-by-step explanation:

tyrone travels 30 miles in 58.2 minutes.  

1 mile = 5280 feet; this means he travels

30(5280) = 158400 feet in 58.2 minutes.

1 minute = 60 seconds; this means he travels 158400 feet in

58.2(60) = 3492 seconds.

this gives us the unit rate of

158400/3492 = 45.36 feet per second.