Me i keep getting stuck on this question

-3 <= x <=8

Step-by-step explanation:

-16 -3|2x-5| >= -49

The first step is to get the absolute value alone.   We need to add 16 to each side.

-16+16 -3|2x-5| >= -49+16

-3|2x-5| >= -33

Now divide each side by -3.  This will flip the inequality.

(-3/-3)|2x-5| =< -33/-3

|2x-5| =< 11

This is where we can separate the absolute value inequality into 2 pieces, one positive and one negative.  Remember to flip the inequality symbol when we take the negative inequality.

2x-5 <=11    and 2x-5>=-11

Add 5 to each side.

2x-5+5 <=11+5    and 2x-5+5>=-11+5

2x<=16                 and  2x>=-6

Divide by 2 on each side.

2x/2<=16/2                 and  2x/2>=-6/2

x <=8        and   x >=-3

Rewrite as a compound inequality

-3 <= x <=8

36 is the final answer! : )

step-by-step explanation:

the multiplicative inverse of a fraction a/b is b/a. for the multiplicative inverse of a real number, divide 1 by the number. for example, the reciprocal of 5 is one fifth 1/5 or 0.2, and the reciprocal of 0.25 is 1 divided by 0.25, or 4.