Which ordered pair is the solution to the system of linear equations -5x+y=26 and 2x-7y=16? (–4, 6) (6, –4) (–4, –6) (–6, –4)

(–6, –4)

Step-by-step explanation:

After converting the two equations from standard form to slope -int form I graphed the two equations on a coordinate plane and found the intersection (in this case solution) of the equation to be (–6, –4)

(–6, –4)

Step-by-step explanation:

This pair of linear equations may be solved simultaneously by using the elimination method. This will involve ensuring that the coefficient of one of the unknown variables is the same in both equations.

It may be solved by substitution in that one of the variable is made the subject of the equation and the result is substituted into the second equation.

Using the substitution method, make y the subject in the first equation

y = 5x + 26

substitute into the second equation

2x -7(5x + 26) = 16

-33x - 182 = 16

-33x = 16 + 182

-33x = 198

x = 198/-33

x = -6

since y = 5x + 26

y = 5(-6) + 26

= -30 + 26

= -4

hence (x,y) = (-6,-4)

step-by-step explanation:

the first 5 right here the next 5 i will upload as separate question

just take the area of the square and then the area of the circle then subtract the circle area from the squares area

step-by-step explanation: