Solve x+2/x-4< 0 a)–4 < x < –2 b)–2 < x < 4 c)–2 < x < –4

Other method:

zeros of numerator and denominator are x = -2 and x = 4.

Look at the second picture.

for x < -2 → x + 2 < 0 and x - 4 < 0

therefore

for -2 < x < 4 → x + 2 > 0 and x - 4 < 0

therefore

for x > 4 → x + 2 > 0 and x - 4 > 0

therefore

damm bro the struggle

step-by-step explanation:

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length