Simplify 6a^-4,b^2,c^8/3a^5,b^-3,c^4

I don't sure but I think this is right

9a^{1} , 2b^{-1} , 2c^{12}

Step-by-step explanation:

6a^{-4} , 3a^{5} =

+ 6a + 3a = 9a

- 4 + 5 = 1

= 9a^{1}

b^{2} , b^{-3} =

+ b + b = 2b

+ 2 - 3 = - 1

= 2b^{-1}

c^{8} , c^{4} =

+ c + c = 2c

+ 8 + 4 = 12

= 2c^{12}

9a^{1} , 2b^{-1} , 2c^{12}

30

step-by-step explanation:

idk

i hope i

hello from mrbilldoesmath!

answer:

the domain is the set { -2, 0, 2, 3}

discussion:

the domain is the set of x values in the ordered pairs (x,y). taking the x, or first component, of each ordered pair gives   -2, 0, 2, 3.

you,

mrb