What are the real zeros of this function. x^3+2x^2-9x-18

x = - 2 , x = - 3, x = 3

Step-by-step explanation:

note that x = - 2 gives

(- 2)³ + 2(- 2)² - 9(- 2) - 18 = - 8 + 8 + 18 - 18 = 0

Hence x = - 2 is a zero and (x + 2) is a factor

x³ + 2x² - 9x - 18 ÷ (x + 2)

= (x + 2)(x² - 9 )

to find zeros, equate to zero

(x + 2)(x + 3)(x - 3) = 0

equate each factor to zero and solve for x

x + 2 = 0 ⇒ x = - 2

x + 3 = 0 ⇒ x = - 3

x - 3 = 0 ⇒ x = 3

the answer is somewhere there guys it really . there im just not gonna answer

step-by-step explanation:

but i'm guessing ur first option tho

trapezoid

step-by-step explanation:

first i plotted all my points on a grid graph

i made sure all of them were in the correct quadrant

then i saw it was a trapezoid or a quadrilateral