The factorization of 8x3 – 125 is (2x – 5)(jx2 + kx + 25). what are the values of j and k? a) j = 6 and k = –10 b) j = 8 and k = 10 c) j = 4 and k = 25 d) j = 4 and k = 10

D

Step-by-step explanation:

8x³ - 125 is a difference of cubes and factors in general as

a³ - b³ = (a - b)(a² + ab + b²)

here 8x³ = (2x)³ ⇒ a = 2x and 125 = 5³ ⇒ b = 5

8x³ - 125 = (2x - 5)((2x)² + (2x × 5) + 5²) = (2x - 5)(4x² + 10x + 25 )

compare the coefficients of like terms with jx² + kx + 25

jx² = 4x² ⇒ j = 4 and kx = 10x ⇒ k = 10 → D

all the angles opposite to the angle 150 would be 150 and all the angles that are next to 150 are 30 because they equal 180 it you add it up.

step-by-step explanation:

49%

step-by-step explanation:

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