The graph of the function, f(x) = x2 - 5x - 7 opens (up/down) and has a (min/max) value.

see explanation

Step-by-step explanation:

given a quadratic in standard form : y = ax² + bx + c : a ≠ 0

Consider the coefficient of the x² term

• If a > 0 then vertex is a minimum and graph opens up

• If a < 0 then vertex is a maximum and graph opens down

f(x) = x² - 5x - 7 is in standard form

with a = 1, b = - 5 and c = - 7

Since a > 0 then vertex is a minimum and graph opens up

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

triangle abc is reflected on the line x=-6.5 then reflected again on the x axis

step-by-step explanation: