Apower line is connecting the top of a building to the ground 260 meters away from the base of the building. at what angle is the wire connected at the building (angle of depression) if the wire is 340 meters long?

Angle of the wire connected at the building ( angle of depression ) is 40.119°  

Step-by-step explanation:

Please refer to the attached figure.

Lets say Tower in figure is represented by AB.

Distance between base of tower and power line ground point is represented by AC = 260 meters

length of the wire that is power line is represented by  BC = 340 meters

Angle of depression = ∠DBC = ∠BCA = x   [  Alternate interior angles ]

consider triangle BAC right angled at A.

cos(x) = (Adjacent side AC)/(Hypotenuse Side BC ) = 260/340 = 0.7647

x = cosinverse ( 0.7647 ) = 40.119°

Hence Angle of the wire connected at the building ( angle of depression ) is 40.119°  

ok then what happened.

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204