Given the line y = 1/3x + 2, write an equation in slope-intercept form of a perpendicular like that passes through (-2, -2).

y = -3x-8

Step-by-step explanation:

y = 1/3x +2

slope is 1/3

parallel is the negative reciprocal

m = -3

point slope form

y-y1 = m(x-x1)

y--2 = -3 (x--2)

y+2 = -3(x+2)

distribute

y+2 = -3x-6

subtract 2 from each side

y = -3x-6-2

y = -3x-8

-13

step-by-step explanation:

f(x)=2x-5 for f(-4)

f(-4)   means let x=-4

f(-4) = 2(-4) -5

f(-4) =-8-5

      = -13