Kobe bryant is shooting free throws. making or missing free throws doesn't change the probability that he will make his next one, and he makes his free throws 83\%83% of the time. what is the probability of kobe bryant making all of his next 6 free throw attempts? choose 1 a)(1−0.83)^6 b)0.83^6 c)6⋅0.83 d)6⋅(1−0.83)

b)0.83^6

probability of Kobe Bryant making all of his next 6 free throw attempts

=probability of Kobe Bryant making first free throw attempts x

probability of Kobe Bryant making second free throw attempts x

probability of Kobe Bryant making third free throw attempts x

probability of Kobe Bryant making fourth free throw attempts x

probability of Kobe Bryant making fifth free throw attempts x

probability of Kobe Bryant making sixth free throw attempts

= P(make 1) x P(make 2nd) x P(make 3rd) x P(make 4th) x P(make 5th)x P(make 6th) = 0.83^6

0.83^6

Step-by-step explanation:

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first, we define the variables:

x: number of years after 1950

f (x): amount of vinyl sold.

then, with the variables defined, we have:

68594 vinyl records were sold in 1958 > f (8) = 68594

91299 vinyl records were sold in 1961 > f (11) = 91299

38720 vinyl records were sold in 1952 > f (2) = 38720

161743 vinyl records were sold in 1967 > f (17) = 161743

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step-by-step explanation: