Me with ***brainliest if 2 ppl answer**

Step-by-step explanation:

Problem One

19 + 2*ln(x) = 25                  Subtract 19 from both sides

19 - 19 + 2ln(x) = 25 - 19      Combine

2* ln(x) = 6                           Divide by 2

ln(x) = 3                                Take the inverse log

e^(ln(x)) = e^3                       Reduce

x = 20.09

Problem 2

Getting this to graph in Desmos can be a bit of trouble.  The correct format is y = abs(x^2 - 3x + 1). Knowing about abs and getting the quadratic to work are two separate [and difficult] problems.

The graph for this is below.

The answers (according to Desmos) are (2,1) and (3.4, 2.4). I think you should include D but that is a matter of opinion. I think it's a typo. Whoever made the question up may actually get that answer.  

there is no image attacted

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!