What is the equation of the line, in slope-intercept form, that passes through the point (0,7) and is perpendicular to the line y=3x−5?

The line would be y = -1/3x + 7

Step-by-step explanation:

In order to find this, we first need to look at the slope of the original equation, which is 3. Perpendicular lines have opposite and reciprocal slopes, which would make the new line's slope -1/3. Knowing this, we can use the slope and the point in point-slope form to get the equation.

y - y1 = m(x - x1)

y - 7 = -1/3(x - 0)

y - 7 = -1/3x

y = -1/3x + 7

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

step-by-step explanation:

sry but any answer choices