If the base of the ladder is 15 feet from the house and reaches 20 feet up the side of the house, what is the length of the ladder? in feet and if a ladder is 10 feet long and the base is 6 feet from the side of the house, how far up the side of the house will the ladder reach?

Part 1: 25 feet long

Part 2: 8 feet high

Step-by-step explanation:

A^2 +B^2 =C^2

C is the hypotenuse which you are finding for part 1.

You are finding B for part 2.

Part 1:

15^2 + 20^2 = C^2

225+400=C^2

625=C^2

Sqrt(625)= C

25=C

Answer for Part 1 is 25 feet long.

Part 2:

6^2 + B^2 = 10^2

36 + B^2 = 100

Subtract 36 from both sides.

B^2 = 64

B= sqrt(64)

B= 8

Answer for Part 2: 8 feet high

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step-by-step explanation:

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for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.