Acompany owns two dealerships, both of which sell cars and trucks. the first dealership sells a total of 164 cars and trucks. the second dealership sells twice as many cars and half as many trucks as the first dealership and sells a total of 229 cars and trucks. how many cars do the two dealerships sell in total

294 cars.

Step-by-step explanation:

Let x be the number of cars and y be the number of trucks.

We have been given that the first dealership sells a total of 164 cars and trucks. We can represent this information as:

The second dealership sells twice as many cars and half as many trucks as the first dealership. So the number of cars sold by 2nd dealership will be 2x and number of trucks sold by 2nd dealership will be y/2.

Further, the 2nd dealership sold a total of 229 cars and trucks. We can represent this information as:

We can see that total number of cars sold on two dealerships will be .

We will use substitution method to solve for x. From equation (1) we will get,

Substituting this value in equation (2) we will get,

Now let us have a common denominator.

Upon multiplying both sides of our equation by 2 we will get,

Therefore, the total number of cars sold by two dealerships is 294.

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

answer: the answer is ann