Mathematics, 29.06.2019 18:30 murphyscott794

Calculate s4 for the sequence defined by {a_n}={19-4n}.

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Answer from: keva1p6dk26

The s_4 term for the sequence is 36.

We have to calculate s4 for the sequence defined by {a_n}={19-4n}.

According to the question,

The given nth term of the sequence is,

$\rm a_n = 19-4n$

Where n is the number of the term.

The first term of the sequence is,

$\rm a_1= 19-4(1)\\\\ a_1 = 19-4\\\\a_1 = 15$

The second term of the sequence is,

$\rm a_2= 19-4(2)\\\\ a_2= 19-8\\\\a_2= 11$

The third term of the sequence is,

$\rm a_3= 19-4(3)\\\\ a_3= 19-12\\\\a_3 = 7$

The fourth term of the sequence is,

$\rm a_4= 19-4(4)\\\\ a_4 = 19-16\\\\a_4= 3$

Therefore,

The s_4 for the sequence is,

$\rm s_4= a_1+a_2+a_3+a_4\\\\s_4 = 15+11+7+3\\\\s_4 = 36$

Hence, The s_4 term for the sequence is 36.

To know more about the Arithmetic progression click the link given below.

link

Answer from: skylex

$S_{4}$ = 36

Step-by-step explanation:

generate the first 4 terms of the sequence using the rule

$a_{1}$ = 19 - 4 = 15

$a_{2}$ = 19 - 8 = 11

$a_{3}$ = 19 - 12 = 7

$a_{4}$ = 19 - 16 = 3

Hence $S_{4}$ = 15 + 11 + 7 + 3 = 36

Answer from: Quest

trapezoid

step-by-step explanation:

first i plotted all my points on a grid graph

i made sure all of them were in the correct quadrant

then i saw it was a trapezoid or a quadrilateral

Answer from: Quest

$a_1 = 1$ , and

$a_{n+1} = a_n + (n + 1)$ for $n \ge 1$

step-by-step explanation:

we can analyze the pattern at which the terms increase. let us denote $a_1 = 1$ , $a_2 = 3$ , $a_3 = 6$ , so that we can call

1 the 1st term, 3 the 2nd term, 6 the 3rd term,etc.

note the following:

from the 1st term (1) to the 2nd term (3), we go up by 2,from the 2nd term (3) to the 3rd term (6), we go up by 3from the 3rd term (6) to the 4th term (10), we go up by 4, andfrom the 4th term (10) to the 5th term (15), we go up by 5.

the pattern: to get the next term value, we just add the next term number (e.g. 1st, 2nd, to the previous term value (term values are the given numbers in the question, 1, 3, 6, 10, 15,

from $a_1 = 1$ , to get to $a_2 = 3$ , we add $2(=1+1)$

from $a_2 = 3$ , to get to $a_3 = 6$ , we add $3 (=2+1)$

etc.

we need to form a recursive formula, a formula that has the next term as a function of the previous term. so a possible recursive formula can be

$a_1 = 1$ , and $a_{n+1} = a_n +(n + 1)$ for $n \ge 1$

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Calculate s4 for the sequence defined by {a_n}={19-4n}....

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