Kite qrst has a short diagonal of qs and a long diagonal of rt. the diagonals intersect at point p. side qr= 5 m and diagonal qs= 6m. find the length of segment rp

Given the statement: Kite QRST has a short diagonal of QS and a long diagonal of RT. The diagonals intersect at point P.

Properties of Kite:

It is given that: Side QR = 5m and diagonal QS = 6m.

Then, by properties of kite:

Substitute the value of QS we get QP;

= 3 m

Now, in right angle

Using Pythagoras theorem:

Substitute the given values we get;

or

Subtract 9 from both sides we get;

Simplify:

Therefore, the length of segment RP is, 4m

Step-by-step explanation:

Firstly, we will draw diagram  for kite

we are given

QR=5m

QS=6m

we know that QPR is a right angled triangle

so, QP=PS

now, we can use Pythagoras theorem

now, we can plug values

0.02

step-by-step explanation:

time of 9 192 631 770 periods of the radiation corresponding to the transition between the 2 hyperfine levels of the ground state of the caesium 133 atom at 0 k (but other seconds are sometimes used in astronomy)