54x+64 greater than or equal to 49x+59 what is x

We want to solve this:

54x + 64 ≥ 49x + 59

First, subtract 49x from both sides and you would get:

5x + 64 ≥ 59

Then subtract 64 from both sides:

5x ≥ -5

Divide both sides by 5:

x ≥ -1

hello from mrbilldoesmath!

answer:   x^2 + y^2 = 1024

discussion:

the equation of a circle with center (h,k) and radius "r" is

(x-h)^2 + (y-k)^2 = r^2.

in our case

(x-0)^2 + (y-0) ^2 = 32^2 = 1024

you,

mrb