Identify the vertex for the graph of y = −3x^2 + 6x − 4 (1, 5) (1, −1) (−1, −13) (−1, −9)

the vertex is (1,-1)

Step-by-step explanation:

y = −3x^2 + 6x − 4

the vertex is at

h= -b/2a  where ax^2 +bx+c

h= -6/2(-3)

h= -6/-6

h=1

substitute this in to find the y value

y = -3(1)^2 +6(1)-4

y = -3+6-4

y = -1

the vertex is (1,-1)