Am is a median in △abc (m∈ bc ). a line drawn through point m intersects ab at its midpoint p. find areas of △apc and △pmc, if area of apm=35m^2.

The area of APC is 70m². The area of triangle PMC is 35m².

Step-by-step explanation:

Let the area of triangle ABC be x.

It is given that AM is median, it means AM divides the area of triangle in two equal parts.

   .....(1)

The point P is the midpoint of AB, therefore the area of APC and BPC are equal.

         ......(2)

The point P is midpoint of AB therefore the line PM divide the area of triangle ABM in two equal parts. The area of triangle APM and BPM are equal.

       .....(3)

The area of triangle APM is 35m².

Therefore the area of triangle ABC is 140m².

Using equation (2).

Therefore the area of triangle APC is 70m².

Using equation (3), we can say that the area of triangle BPM is 35m² and by using equation (2), we can say that the area of triangle BPC is 70m².

Therefore the area of triangle PMC is 35m².

idk

step-by-step explanation:

do it yourself, cause that made me do it myself today, in english!

600,000,000,000, or 6e14

step-by-step explanation: