Answer both questions and show all work with explanations : ) you soo 1) the lengths of the sides of a rectangle are 60 cm and 91 cm. what is the length of a diagonal? 2) the perimeter of a rectangle is 46 in and the diagonal is 17 in. find the area of the rectangle.

1) 109 cm

2) 120 in²

Step-by-step explanation:

A rectangle is a quadrilateral with opposite sides the same length and four (4) right angles. The diagonal, together with two adjacent sides, forms a right triangle. The relationship between side lengths and the diagonal length is given by the Pythagorean theorem. If sides are "a" and "b" and the diagonal is "c", that theorem tells you ...

... c² = a² + b²

1) c² = (60 cm)² + (91 cm)² = 11881 cm²

... c = √11881 cm = 109 cm

2) The perimeter is double the sum of adjacent side lengths, so ...

... 2(a+b) = 46 in

... a + b = 23 in . . . . . divide by 2

The Pythagorean theorem tells you

... a² + b² = (17 in)²

Squaring the equation from the perimeter relation gives ...

... (a + b)² = (23 in)² = a² + 2ab + b²

Subtracting a² + b², we have

... (a² +2ab +b²) - (a² + b²) = (23 in)² -(17 in)²

... 2ab = (529 -289) in² = 240 in² . . . . . simplify

... 240 in²/2 = ab = 120 in² . . . . . area is the product of length and width

We could solve the two equations for a and b to find that there are two possible solutions: (a, b) = (8, 15) or (15, 8). Either way, ab = 8·15 = 120.

first one is a: renaming a fraction. second one is c: de-c

step-by-step explanation:

my explanation is that these were the answers on edg : )