Two buses left town a for town b at the same time. the speed of one of the buses was 10 mph greater than the speed of the other bus. in 3 1/2 hours one bus reached town b, while the other bus was away from town b at a distance equal 1/6 of the distance between a and b. find the speed of the buses and the distance between a and b.

Speed of slower bus = 50mph and

speed of faster bus = 60 mph

Step-by-step explanation:

Let speed of first bus be x mph

Then speed of second bus = x+10 mph.

Let A and B have a distance d.

Then given that faster bus reached in 3.5 hours.

i.e. ... i

THe other bus was away from B by 1/6 times d.

Distance travelled by slower bus = 1-1/6 = 5d/6  

Time taken = 3.5 hours

i.e. ... ii

Divide i by ii to eliminate d.

ie Speed of slower bus = 50mph and

speed of faster bus = 60 mph

Use ii equation

miles

The speed of the bus = 50 mph and 60 mph

The distance between town A and town B : 210 miles

Linear motion consists of 2: constant velocity motion with constant velocity and uniformly accelerated motion with constant acceleration

• At constant velocity motion:

the speed of vo = v = constant

acceleration = a = 0

Δx = vt or x = xo + vt

An equation of constant velocity motion

x = distance = m

v = speed = m / s

t = time = seconds

The velocity graph (v) versus time (t) (v on the y axis and t on the x axis) shows a straight line parallel to the x axis (= time) because it has a constant speed

While the displacement of objects (Δx) is the area under the v-t line

Two buses left town A for town B

The speed for B1(first bus) = v

The speed for B2(second bus) = 10+v⇒10 mph greater

In 3.5 hours :

B1 reached town B, while B2 at the distance a distance equal 1/6 of the distance between A and B, then :

x = displacement of B1

x-1/6x=5/6x =  displacement of B2

Because time = t = displacement(x) : speed(v),

in 3.5 hours :

time for B1 = time for B2

So speed the first bus ,B1 = 50 mph and speed the second bus, B2 = 10+50 = 60 mph

The distance from town A and town B (use t1=time for B1)

The distance of the elevator  

link  

resultant velocity  

link  

the average velocity  

link  

c is the final answer! : )

i don't have the answer rn but go to math papa. it shows the steps and the answer. hope this : )

step-by-step explanation: