Given the system of equations presented here: 4x + y = 4 2x + 7y = 28 which of the following actions creates an equivalent system such that, when combined with the other equation, one of the variables is eliminated? (5 points) multiply the second equation by −1 to get −2x − 7y = −28 multiply the second equation by −4 to get −8x − 28y = −112 multiply the first equation by −7 to get −28x − 7y = −28 multiply the first equation by −2 to get −8x − 2y = −8

multiply the first equation by - 7 to get - 28x - 7y = - 28

Step-by-step explanation:

This then results on  adding the 2 equations as

- 24x = 0 ⇒ x = 0 and y = 4

solution to system is (0, 4 )

multiply the first equatiom by -7 to get -28x -7y =-28

Step-by-step explanation:

4x + y = 4 (1)

2x + 7y = 28 (2)

multiply equation (1) by -7

-28x - 7y = -28 (3)

add equation (2) and (3)

-24x = 0

Divide bothside by 24

x =0

substitute x= 0 in equation(1)

4x +y = 4

4(0) + y = 4

y = 4

step-by-step explanation:

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3