Of the people who fished at clearwater park today, 54 had a fishing license and 36 did not. of the people who fished at mountain view park today, 70 had a license, and 30 did not. (no one fished both parks.) suppose that one fisher from each park is chosen at random. what is the probability that the fisher chosen from clearwater had a license and the fisher chosen from mountain view did not have a license? do not round answer.

For Clearwater Park, the probability is 40%. For Mountain View Park, the probability is 30%.

At Clearwater Park, there was total of 90 people (54+36). 36 of them did not have a fishing license. That is , that is 0.4. Now, we multiply that 100% and we get, that the chance is 40%.

At Mountain View Park, there was total of 100 people (70+30). 30 of them did not have a fishing license. That is , that is 0.3. Now, we multiply that 100% and we get, that the chance is 30%.

I hope I helped you. I will be really happy, If you mark my answer as the brainliest.Your David

i don't have the answer rn but go to math papa. it shows the steps and the answer. hope this : )

step-by-step explanation: