What is the missing constant term in the perfect square that starts with x^2-12x

Essentially, we are trying to find the missing constant term of (remember that we are subtracting due to the negative sign in front of the second term). Let's expand this to see what we can work with:

Now, we know the second term is , so let's set the second term in the polynomial we just found equal to :

We have found . We know the missing constant term is , according to the polynomial we found earlier. Thus, the missing term is:

The missing constant term is 36.

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2

is this part of a question or something