For the quadratic relation y = -3x2 - 7x + 8, a) state the y-intercept b) determine the zeros, to 1 decimal place (show your process) c) use your results from a) and b), to clearly graph and label this quadratic relation. include your graph image or link here.

y intercept  (0,8)

zero's ( -3.2 ,0) (.8,0)

Step-by-step explanation:

y = -3x2 - 7x + 8,

to find the y intercept, set x = 0

y = 0-0+8

the y intercept is 8

y = -3x2 - 7x + 8,

use the quadratic equation to find the zeros

-b ±sqrt(b^2 -4ac)

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         2a

-(-7) ±sqrt((-7)^2 -4*(-3)*8)

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           2*(-3)

(7) ±sqrt((49 +96)

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           -6

(7) ±sqrt((145)

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           -6

(7+ sqrt(145))/-6  =-3.173599       round to 1 decimal place   -3.2

and

(7- sqrt(145))/ -6=.840266   round to 1 decimal place   .8

idk

step-by-step explanation:

a

step-by-step explanation: