Plz 50 or 25, a nature museum has 2008 specimens of early birds, some with 2 wings and some with 4 wings. the specimens have a total of 4038 wings. how many specimens are there with each number of wings?

there are 1997 two winged specimens and

11 four winged specimens

Step-by-step explanation:

t = two winged specimens

f = 4 winged specimens

2*t + 4*f = 4038   4038 wings

t+f =2008              2008 specimens

solve for t

t= 2008 -f

substitute t into 2*t + 4*f = 4038

2*(2008-f) + 4*f = 4038

distribute

2*2008 -2f + 4f = 4038

4016 -2f + 4f = 4038

combine like terms

4016 +2f = 4038

subtract 4016 on each side

2f = 4038 -4016

2f = 22

divide by 2

f = 22/2 =11

there are 11 4 winged specimens

t = 2008 - f

t = 2008-11

t =1997

s + (a + 178) = 2000

step-by-step explanation:

2000 - 178 = 1822

1822 / 2 = 911

911 + 178 = 1089

1089 + 911 = 2000

abha = 1089

shane = 911

answer:

c 60% on edg