Applying the quadratic formula the height h (in feet) of an object t seconds after it is dropped can be modeled by the quadratic equation h = -16t2 + h0, where h0 is the initial height of the object. suppose a small rock dislodges from a ledge that is 255 ft above a canyon floor. solve the equation h = -16t2 + 255 for t, using the quadratic formula to determine the time it takes the rock to reach the canyon floor. a)t ≈ 0.87 s b)t ≈ 4 s c)t= 8.5 s d)t = 16 s

B

Step-by-step explanation:

The trick you need to employ is that when the rock hits the ground, the timer stops. So h must be taken as 0.

0 = - 16t^2 + 255            Set up the equation

- 255 = - 16t^2                Divide by -16

15.9375 = t^2                  Switch

t^2 = 15.9375                   Take the square root of both sides.

sqrt(t^2) = sqrt(15.9375)

t = 3.992 seconds

The closest answer is B

the answer is 45 i just did it on oddesy ware

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: