The members of the boosters organization at your high school bought new balls for the school. they spent $22.00 per basketball and $30.00 per football, spending a total of $648.00. they bought 6 more footballs than basketballs. how many of each type of ball did they buy?

9 basket balls, 15 foot balls

Step-by-step explanation:

Let x be the number of basket ball

y be the number of foot ball

1 basket ball = $22

so x basket ball = 22x

1 foot ball = $30

so y foot ball = 30y

Total cost = 648

The equation becomes 22x+ 30y = 648

Given : They bought 6 more footballs than basketballs.

foot  ball (y) = 6 more basket balls(x)

so y = x + 6

we solve for  x  and y

Now we plug in x+6 for y in the equation 22x+ 30y = 648

22x+ 30(x+6) = 648

22x + 30x + 180 = 648

Subtract 180 on both sides

52x = 468

Divide both sides by 52

so x= 9

Number of basket ball x= 9

Number of foot ball y=x+6= 9+ 6 = 15

just put them in order

step-by-step explanation:

$4

step-by-step explanation:

$30×5=$150

$150 minus $130=$20

$20÷5=$4.

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