In a single experiment, a die is tossed and a spinner with the letters a, b, and c is spun. each letter is equally likely. find the sample space and then find the probability of getting a b. a.the sample space is 18. the probability of getting a b is 1/9b. the sample space is 18. the probability of getting a b is 1/3c. the sample space is 9. the probability of getting a b is 1/9d. the sample space is 9. the probability of getting a b is 1/18

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

i belive those are the ones that are under 90 degreese.