Out of 54 randomly selected patients of a local hospital who were surveyed, 49 reported that they were satisfied with the care they recieved. construct and interpret a 95% confidence interval for the percentage of all patients satisfied with their care at the hospital.

The 95% confidence interval is given below:

Where:

is the critical value at 0.05 significance level

is the sample size

Therefore, the 95% confidence interval for the percentage of all patients satisfied with their care at the hospital is    

16.9 times 2.85

step-by-step explanation:

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)