How do i solve 1/3h-4(2/3h-3)=2/3h-6

6.. I think

Step-by-step explanation:

h in (-oo:+oo)

(1/3)*h-(4*((2/3)*h-3)) = (2/3)*h-6 // - (2/3)*h-6

(1/3)*h-(4*((2/3)*h-3))-((2/3)*h)+6 = 0

(1/3)*h-4*((2/3)*h-3)+(-2/3)*h+6 = 0

h/3-4*(2/3*h-3)+(-2*h)/3+6 = 0

(-4*3*(2/3*h-3))/3+h/3+(-2*h)/3+(3*6)/3 = 0

h-4*3*(2/3*h-3)-2*h+3*6 = 0

18-7*h-2*h+36 = 0

18-9*h+36 = 0

54-9*h = 0

(54-9*h)/3 = 0

(54-9*h)/3 = 0 // * 3

54-9*h = 0

54-9*h = 0 // - 54

-9*h = -54 // : -9

h = -54/(-9)

h = 6    

the answer for your question is

step-by-step explanation: